Answer:
Explanation:
Given
Four Point charges are Placed at the corner of a square with side length a
Length of diagonal [tex]a\sqrt{2}[/tex]
Distance of charge from center [tex]\frac{a\sqrt{2}}{2}=\frac{a}{\sqrt{2}}[/tex]
Potential at the center due to four charges is given by
[tex]V=\frac{4\cdot k\cdot Q}{\frac{a}{\sqrt{2}}}[/tex]
as all the four charges are equal and placed symmetrical about center
Work done required to bring a fifth charge q from infinity to the center of the square
[tex]W=qV[/tex]
[tex]W=\frac{4\sqrt{2}kQq}{a}[/tex]
