Answer:
Van't Hoff factor, for this solution is 3.2
Explanation:
Osmotic pressure formula → π = M . R . T . i
π = Pressure → 3.85 atm
M = Molarity → 0.05mol/L
R = Constant for the Ideal Gases → 0.082 L.atm / mol.K
T = Absolute T° (K) → T°C + 273
20°C + 273 = 293K
Let's replace data:
3.85 atm = 0.05 mol/L . 0.082 L.atm/mol.K . 293K . i
3.85 atm / 0.05 . 0.082 atm . 293 = i
3.20 = i
If we assume complete ionization, i must be ≅ 4
AlCl₃ → Al³⁺ + 3Cl⁻
We have 1 mol of aluminum cation and 3 moles of chloride, 4 total moles.
