Answer:
θ = 4.092 °
Explanation:
Given that
Initial Angular speed ,ωi = 0.76 rad/s
Final angular speed ,ωf= 2.96 rad/s
The angular acceleration ,α = 1 rad/s²
We know that
ωf² = ωi ²+ 2 α θ
θ=Angle rotates
2.96² = 0.76²+ 2 x 1 x θ
[tex]\theta=\dfrac{2.96^2-0.76^2}{2}\ degrees\\\theta=4.092\ degrees\\[/tex]
Therefore the angle rotates by machine part will be 4.092 degrees.
θ = 4.092 °
