Respuesta :
Answer:
Explanation:
Given
Temperature of gas at First stage [tex]T_1=0^{\circ}C\approx 273\ K[/tex]
Pressure of gas at First stage [tex]P_1=760\ torr[/tex]
Volume Occupies [tex]V_1=22.4\ L[/tex]
If the Pressure and Temperature at second stage is
[tex]P_2=760\ torr[/tex]
[tex]T_2=25^{\circ}C\approx 298\ K[/tex]
Using ideal gas Equation
[tex]PV=nRT[/tex]
where P=Pressure
V=volume
R=Universal Gas constant
T=Temperature
n=no of moles
as n and R is constant therefore
[tex]\frac{PV}{T}=constant[/tex]
thus [tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
[tex]V_2=\frac{760}{760}\times \frac{298}{273}\times 22.4[/tex]
[tex]V_2=24.45\ L[/tex]
