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A sample of natural gas contains 8.24 moles of CH4, 0.421 moles of C2H6, and 0.116 moles of C3H8. If the total pressure of the gases is 1.37 atm, what is the partial pressure of propane (C3H8)

Respuesta :

princessesther2011

Answer:

The partial pressure of propane is 0.018 atm

Explanation:

Moles of propane = 0.116 moles

Total moles of gas mixture = 8.24+0.421+0.116 = 8.777 moles

Total pressure of gas mixture = 1.37 atm

Partial pressure of propane = 0.116/8.777 × 1.37 atm = 0.018 atm

Lanuel

The partial pressure of propane ([tex]C_3H_8[/tex]) is equal to 0.0181 atm.

Given the following data:

  • Number of moles of [tex]CH_4[/tex] = 8.24 moles.
  • Number of moles of [tex]C_2H_6[/tex] = 0.421 moles.
  • Number of moles of [tex]C_3H_8[/tex] = 0.116 moles.
  • Total pressure = 1.37 atm

To determine the partial pressure of propane ([tex]C_3H_8[/tex]):

First of all, we would find the total number of moles of the chemical compounds:

[tex]n=8.24+0.421+0.116[/tex]

n = 8.777 moles

Next, we would determine the mole fraction of propane by using this formula:

[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}\\\\Molefraction \;of \;a \;substance =\frac{0.116}{8.777} \\\\Molefraction \;of \;a \;substance =0.0132[/tex]

For propane:

[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.0132 \times 1.37[/tex]

Partial pressure of  = 0.0181 atm.

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