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A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each solution should be used if 28 28 gallons of the 18 % 18% solution are needed?

Respuesta :

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

[tex]C_1[/tex] = concentration of ist disinfectant solution = 16 %

[tex]V_1[/tex] = volume of pure acid solution = x gallons

[tex]C_2[/tex] = concentration of another disinfectant solution= 23%

[tex]V_2[/tex] = volume of another acid solution= (28-x) gallons

[tex]C_3[/tex] = concentration of resulting disinfectant solution = 18 %

[tex]V_1[/tex] = volume of resulting acid solution = 28 gallons

[tex]16\times x+23\times (28-x)=18\times 28[/tex]

[tex]x=20galllons[/tex]

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

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