What is the length of AC in the given triangle?
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Answer:
A
Step-by-step explanation:
We require to find ∠ A
Subtract the sum of the given angles from 180
∠ A = 180° - (85 + 53)° = 180° - 138° = 42°
Using the Sine rule in Δ ABC, that is
[tex]\frac{BC}{sin42}[/tex] = [tex]\frac{AC}{sin85}[/tex] , that is
[tex]\frac{85}{sin42}[/tex] = [tex]\frac{AC}{sin85}[/tex] ( cross- multiply )
AC × sin42° = 85 × sin85° ( divide both sides by sin42° )
AC = [tex]\frac{85sin85}{sin42}[/tex] ≈ 126.6