[tex](y+3)(2y+y-3y+4) = 4y + 12[/tex]
Solution:
Given expression is:
[tex](y+3)(2y+y-3y+4)[/tex]
We have to find the product
From given expression,
[tex](y+3)(2y+y-3y+4)[/tex]
Combine the like terms in second parenthesis
[tex](y+3)(3y - 3y + 4)\\\\(y+3)(4)[/tex]
By distributive property,
(a + b)c = ab + ac
Therefore,
[tex](y+3)4 = 4y + 12[/tex]
Thus the product is found
