Answer:
Therefore, the hardness of the water in mol/L is 0.00134 mol/L
Explanation:
100ppm = 0.1g/L
134ppm = 134 × 0.1/100 = 0.134 g/L
Concentration in mol/L = (Concentration in g/L)/(molar mass)
Molar mass of CaCO₃ = 100.1 g/mol
Concentration In mol/L = 0.134/100.1 = 0.00134 mol/L
Therefore, the hardness of the water in mol/L is 0.00134 mol/L
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