(9x 10^-3)^2=[tex]\frac{81x^{2}}{1000000}[/tex], so d 8.1x10^-6
Evaluate 1/2a^-4b^2 for a =-2 and b=4
[tex]\frac{1}{2} (-2)^{-4} *4^{2}\\\\\frac{1}{2} *\frac{1}{(-2)^{4}} *4^{2}\\\\\frac{1}{2} *\frac{1}{2^{4}}*4^{2}\\\\\frac{1}{2} *\frac{1}{16}*4^{2}\\\\\frac{1}{2} *\frac{1}{16}*16=\frac{1}{2}[/tex]
A number raised to a negative exponent is sometimes negative.
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)
- Cutiepatutie ☺❀❤
