Someone help me with this. I forgot my notes in class
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Answer:
see explanation
Step-by-step explanation:
Since AB = BC the the triangle is isosceles and thus
∠ A = ∠ C = 8x
The sum of the 3 angles in a triangle = 180°
Sum the 3 angles and equate to 180
44x + 8x + 8x = 180, that is
60x = 180 ( divide both sides by 60 )
x = 3
Thus
∠ A = ∠ C = 8x = 8(3) = 24°
∠ B = 44x = 44(3) = 132°
Step-by-step explanation:
[tex] In\: \triangle ABC\\\\
BA = BC... (Given) \\\\
\therefore \angle BAC = \angle BCA \\(Angles \:opposite\: to \:equal\:\\sides\:are\: equal) \\\\
\because m\angle BCA= 8x... (Given) \\\\
\therefore \angle BAC = 8x\\\\
In\: \triangle ABC\\\\
m\angle ABC + m\angle BAC + m\angle BCA \\= 180\degree \\\\
\therefore \: 44x + 8x + 8x = 180\degree \\\\
\therefore \: 60x= 180\degree \\\\
\therefore \: x= \frac{180\degree}{60} \\\\
\therefore \: x= 3\degree\\\\
\therefore \: m\angle B =44x = 44\times 3\degree\\\\
\therefore \: m\angle B =132\degree\\\\
m\angle A= m\angle C=8x =8 \times 3\degree\\\\
\therefore \: m\angle A= m\angle C= =24\degree[/tex]