Answer:
46g of sodium acetate.
Explanation:
The data is: Precipitation from a supersaturated sodium acetate solution. The solution on the left was formed by dissolving 156g of the salt in 100 mL of water at 100°C and then slowly cooling it to 20°C. Because the solubility of sodium acetate in water at 20°C is 46g per 100mL of water, the solution is supersaturated. Addition of a sodium acetate crystal causes the excess solute to crystallize from solution.
The third solution is the result of the equilibrium in the solution at 20°C. As the maximum quantity that water can dissolve of sodium acetate at this temperature is 46g per 100mL and the solution has 100mL there are 46g of sodium acetate in solution. The other sodium acetate precipitate because of decreasing of temperature.
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Based on the solubility of sodium acetate at 20°C, the grams of sodium acetate present in the third breaker if it is a saturated solution is 46 g.
Solutions are substances formed when a substance known as solute dissolves in another substance known as the solvent.
The amount of a solute dissolved in a given volume of solvent at a given temperature is known as the solubility of that solute at that temperature.
The solubility of a solute increases with increase in temperature.
At 20°C, the solubility of sodium acetate is 46 g/100mL of water.
Therefore, the grams of sodium acetate present in the third breaker if it is a saturated solution is 46 g.
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