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an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at a speed of 8m/s at the top. what was the force exerted by the track on the cart at the top of the loop?

Respuesta :

Answer:

F=  224 N

Explanation:

Given that

mass ,m = 80 kg

Radius ,r= 5 m

speed at the top v= 8 m/s

The force at the top = F

Now by using the Second law of Newton's

[tex]F+mg=\dfrac{mv^2}{r}[/tex]

Now by putting the values

[tex]F+80\times 10 = \dfrac{80\times 8^}{5}[/tex]

Take  g = 10 m/s²

[tex]F= \dfrac{80\times 8^2}{5}-800[/tex]

F=  224 N

Therefore the force exerted by the track at the top position will be 224 N.

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