Answer:
The angle between the velocity and acceleration vectors at perihelion and aphelion is between 0 to 90 degree and 90 to 100 degrees respectively
Explanation:
To understand this consider a planet is moving around sun in orbital motion as shown in figure attached below. Point A is perihelion (close to sun) and point B is aphelion (far away from sun), instantaneous orbital speed is:
[tex]v=\sqrt{\mu(\frac{1}{r}-\frac{1}{d})}[/tex]
r is radius of ellipse and d is elliptical distance between body in orbital motion w.r.to center body (planet and sun respectively).
As shown from fig
[tex]d_{a}<d_{b}[/tex]
so this defines clearly that according to Kepler's law of orbital motion, Orbital speed at perihelion (point A) is greater than orbital speed at aphelion (point B)
The angle between the velocity and acceleration vectors at perihelion and aphelion is between 0 to 90 degree and 90 to 100 degrees respectively
