Answer : The correct option is, (b) [tex]1.3\times 10^{-3}M[/tex]
Explanation :
According to the Henry's law:
[tex]C_{O_2}=k_H\times p_{O_2}[/tex]
where,
[tex]C_{O_2}[/tex] = molar concentration of [tex]O_2[/tex] = ?
[tex]p_{O_2}[/tex] = partial pressure of [tex]O_2[/tex] = 1.0 atm
[tex]k_H[/tex] = Henry's law constant = [tex]1.3\times 10^{-3}mole/L.atm[/tex]
Now put all the given values in the above formula, we get:
[tex]C_{O_2}=(1.3\times 10^{-3}mole/L.atm)\times (1.0atm)[/tex]
[tex]C_{O_2}=1.3\times 10^{-3}mole/L=1.3\times 10^{-3}M[/tex]
Therefore, the molar concentration of oxygen in water is, [tex]1.3\times 10^{-3}M[/tex]
