Answer:
V=483.63 m/s
Explanation:
Given that
mass ,m= 5.31 x 10⁻²⁶ kg
Kinetic energy KE= 6.21 x 10⁻²¹ J
As we know that the kinetic energy of the mass m with moving velocity V given as
[tex]KE=\dfrac{1}{2}mV^2[/tex]
Now by putting the values
[tex]6.21\times 10^{-21}=\dfrac{1}{2}\times 5.31\times 10^{-26}\times V^2[/tex]
[tex]V^2=\dfrac{2\times 6.21\times 10^{-21}}{5.31\times 10^{-26}}[/tex]
[tex]V^2=233898.30[/tex]
[tex]V=\sqrt{233898.30}\ m/s[/tex]
V=483.63 m/s
Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.
