Respuesta :

abidemiokin

Answer:

26.1°C

Explanation:

Initial temperature of an ideal gas is 29°C. If the thermal energy is reduced by 10% after cooling, the temperature of the gas has reduced by (10% of 29°C)

= 0.1×29

= 2.9°C

The new temperature = initial temperature - reduction

= 29°C - 2.9°C

= 26.1°C

Cricetus

The new temperature will be "26.1°C".

Given:

Initial temperature,

  • 29°C

Reduced thermal energy,

  • 10% or 0.1

The reduction will be:

= [tex]0.1\times 29[/tex]

= [tex]2.9^{\circ} C[/tex]

hence,

The new temperature will be:

= [tex]Initial \ temperature - Reduction[/tex]

= [tex]29- 2.9[/tex]

= [tex]26.1^{\circ} C[/tex]

Thus the above answer is right

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