Answer:
velocity of other bullet will be [tex]v_2^2=\sqrt{2}v_1[/tex]
As kinetic energy of both bullet are same so they will do same amount of work
Explanation:
We have given that two bullets are fired with same kinetic energy
So [tex]KE_1=KE_2[/tex]
Let the mass of bullet 1 is [tex]m_1[/tex] and mass of bullet 2 is [tex]m_2[/tex]
And their velocity are [tex]v_1[/tex] and [tex]v_2[/tex]
According to question [tex]m_1=2m_2[/tex]
So [tex]\frac{1}{2}\times 2m_2\times v_1^2=\frac{1}{2}\times m_2\times v_2^2[/tex]
[tex]v_2^2=2v_1^2[/tex]
[tex]v_2^2=\sqrt{2}v_1[/tex]
So velocity of other bullet will be [tex]v_2^2=\sqrt{2}v_1[/tex]
As kinetic energy of both bullet are same so they will do same amount of work
