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A potters wheel moves from rest to an angular speed of 0.10 rev/s in 32.5 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2? Answer in units of rad/s.

Respuesta :

MathPhys

Answer:

0.019 rad/s²

Explanation:

Given:

ω₀ = 0 rad/s

ω = 0.10 rev/s = 0.628 rad/s

t = 32.5 s

Find: α

ω = αt + ω₀

0.628 rad/s = α (32.5 s) + (0 rad/s)

α = 0.019 rad/s²

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