Answer:
Pb²⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s)
Explanation:
There are three steps you must follow. You must write the:
- Molecular equation
- Ionic equation
- Net ionic equation
A. Molecular equation
Pb(NO₃)₂(aq) + 2KI(aq) ⟶ PbI₂(s) + 2KNO₃(aq)
B. Ionic equation
You write all the soluble substances as ions.
Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
C. Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
The net ionic equation is
Pb²⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s)
