aslanborjiko aslanborjiko
  • 12-01-2020
  • Mathematics
contestada

(x + y)² +r ² = (x+y+r)
[tex](x\ + y) {}^{2} + r {}^{2} = (x + y + r) {}^{2} [/tex]
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Respuesta :

treymo1w
treymo1w treymo1w
  • 12-01-2020
X=0
Y=0
R=1
R can be two things 1 or 0 but I think one is the answer they are looking for
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