Answer:
Explanation:
Instant Velocity and Acceleration
Give the position of an object as a function of time y(x), the instant velocity can be obtained by
[tex]v(x)=y'(x)[/tex]
Where y'(x) is the first derivative of y respect to time x. The instant acceleration is given by
[tex]a(x)=v'(x)=y''(x)[/tex]
We are given the function for y
[tex]y(x)=3.0+4.8x +6.4x^2[/tex]
Note we have changed the last term to be quadratic, so the question has more sense.
The velocity is
[tex]v(x)=y'(x)=4.8+12.8x[/tex]
And the acceleration is [tex]a(x)=v'(x)=12.8[/tex]
