Respuesta :
Answer:
2FeCl3(aq) + 3(NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)
Explanation:
Step 1: Data given
The reactants are:
iron(III) chloride = FeCl3
ammonium sulfide = (NH4)2S
The products are:
ammonium chloride = NH4Cl
iron(III) sulfide = Fe2S3
Step 2: Balance the reaction
FeCl3(aq) + (NH4)2S(aq) → NH4Cl(aq) + Fe2S3(s)
On the right side we have 2x Fe, so on the left side, to balance the amount of Fe on both sides, we should multiply FeCl3 by 2
2FeCl3(aq) + (NH4)2S(aq) → NH4Cl(aq) + Fe2S3(s)
On the left side we have 6x Cl, on the right side 1x Cl. To balance the amount of Cl we have to multiply NH4Cl (on the right side) by 6
2FeCl3(aq) + (NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)
On the right side we have 6x NH4, on the left side we have 2x NH4. To balance this amount we should multiply (NH4)2S on the left side by 3
Now the reaction is balanced.
2FeCl3(aq) + 3(NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)
The balanced equation for the reaction between aqueous iron(III) chloride and aqueous ammonium sulfide to produce aqueous ammonium chloride and solid iron(III) sulfide is:
2FeCl₃ (aq) + 3(NH₄)₂S (aq) —> 6NH₄Cl (aq) + Fe₂S₃ (s)
The equation for the reaction between aqueous iron(III) chloride and aqueous ammonium sulfide to produce aqueous ammonium chloride and solid iron(III) sulfide can be written as follow:
Iron (III) chloride => FeCl₃
Ammonium sulfide => (NH₄)₂S
Ammonium chloride => NH₄Cl
Iron(III) sulfide => Fe₂S₃
Iron (III) chloride + Ammonium sulfide —> Ammonium chloride + Iron(III) sulfide
FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃
The above equation can be balance as follow:
FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃
There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by writing 2 before FeCl₃ as shown below:
2FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃
There are 3 atoms of S on the right side and 1 atom on the left side. It can be balance by writing 3 before (NH₄)₂S as shown below:
2FeCl₃ + 3(NH₄)₂S —> NH₄Cl + Fe₂S₃
There are 6 atoms of Cl on the left side and 1 atom on the right side. It can be balance by writing 6 before NH₄Cl as shown below:
2FeCl₃ (aq) + 3(NH₄)₂S (aq) —> 6NH₄Cl (aq) + Fe₂S₃ (s)
Now, the equation is balanced!
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