Respuesta :
Answer:
Δω = -5.4 rad/s
αav = -3.6 rad/s²
Explanation:
Given:
Initial angular velocity = ωi = 2.70 rad/s
Final angular velocity = ωf = -2.70 rad/s (negative sign is
due to the movement in opposite direction)
Change in time period = Δt = 1.50 s
Required:
Change in angular velocity = Δω = ?
Average angular acceleration = αav = ?
Solution:
Angular velocity (Δω):
Δω = ωf - ωi
Δω = -2.70 - 2.70
Δω = -5.4 rad/s.
Average angular acceleration (αav):
αav = Δω/Δt
αav = -5.4/1.50
αav = -3.6 rad/s²
Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.
Answer: The change in angular velocity is -5.40rad/s
And acceleration is -3.6rad/s
Explanation:
Given that;
The initial angular velocity wi is 2.70rad/s and
The final angular velocity wf is -2.70rad/s
The time taken ∆t is 1.50s.
( For angular velocity counterclockwise direction is positive while clockwise direction is negative)
The change in the angular velocity ∆w can be written as;
∆w = wf - wi
∆w = -2.70 - 2.70
∆w = -5.40rad/s
The angular acceleration Ar which is the change in angular velocity per unit time is;
Ar = ∆w/∆t
Ar = -5.40/1.5
Ar = -3.6rad/s^2
Therefore the change in angular velocity is -5.40rad/s
And acceleration is -3.6rad/s
