Answer
given,
wavelength of laser light = 632.8 nm
assuming that aperture of lens be equal to dia = 1 mm
now,
When laser light passes through aperture diffraction of light takes place
The first diffraction minima occurs at
[tex]a sin (p) =\lambda[/tex]
where a is the width of aperture
λ is the wavelength of light
p is the angle
[tex]sin (p) =\dfrac{\lambda}{a}[/tex]
[tex]sin (p) =\dfrac{632.8\times 10^{-9}}{1 \times 10^{-3}}[/tex]
[tex]p =sin^{-1}(0.0006328)[/tex]
p = 0.0363° angle of the first dark ring
