Answer:
4.25 m/s
Explanation:
Force, F = 22 N
Time, t = 0.029 s
mass, m = 0.15 kg
initial velocity of the cue ball, u = 0
Let v be the final velocity of the cue ball.
Use newton's second law
Force = rate of change on momentum
F = m (v - u) / t
22 = 0.15 ( v - 0) / 0.029
v = 4.25 m/s
Thus, the velocity of cue ball after being struck is 4.25 m/s.
Answer:
4.25 m/s
Explanation:
An impulse is defined as a change in momentum, and can be found my multiplying an applied force by its duration. In this case,
that's 22×0.029 = 0.638 kg-m/s. Momentum is also mass times velocity, and your velocity is unknown.
Momentum P= mv
0.15 v= 0.638
v= 4.25 m/s
