Answer:
let us suppose the first no. is x and second no is y
According to 1st condition
x+y=20.................................. .............1
4x-y=10...... .. . ........... . ............... ..2
add both
x=6
put x=6 in 1
6+y=20
y= 20 -6
y=6
3,6
Answer:the first number is 5
The second number is 10
Step-by-step explanation:
Let x represent the first number.
Let y represent the second number.
A number doubled and added to a second number is equal to 20. This means that
2x + y = 20 - - - - - - - - - -1
Four times the first number minus the second number is equal to 10. This means that
4x - y = 10 - - - - - - - - - - -2
We would eliminate y by adding equation 1 and equation 2. It becomes
6x = 30
x = 30/6 = 5
Substituting x = 5 into 2x + y = 20, it becomes
2 × 5 + y = 20
10 + y = 20
y = 20 - 10 = 10
