Answer:
Keq for the reaction (option a)
Explanation:
This is the equilbrium
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
The expression for Kc is this:
Kc = [SO₃]² / [O₂] . [SO₂]²
If we add O₂, we are increasing reactant side, so when we reach the new equilibrium, Kc will be lower.
Kc ↓ = [SO₃]² / [O₂] ↑ . [SO₂]²
- If we add O₂, total pressure will be increased.
- The amount of SO₃ will also increase. As we pertubate the reactant side, the reaction has to promote produc synthesis, to reach the new equilibrium.
Out of equilibrium we talk about Qc (quotient reaction) - The expression is the same but we apply Qc when we are not in eq.
Qc ↓ = [SO₃]² / [O₂] ↑ . [SO₂]²
If Qc < Kc some reactants have to be transformed into products
- The amount of SO₂ is still the same.
- If we add O₂, partial pressure of it, will be increased, so the total pressure will also increase.