25.) Solve the compound inequality.
2x – 2 < –12 or 2x + 3 > 7

a.) x < –7 or x > 5

b.) x < –5 or x > 5

c.) x < –5 or x > 2

d.) x < –12 or x > 2

Question

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Respuesta :

absor201 absor201 · Answer 1 · 2020-01-18T04:47:20+01:00

The right answer is Option C: x< -5 or x>2

Step-by-step explanation:

Given inequalities are;

2x – 2 < –12 or 2x + 3 > 7

We will solve first inequality;

2x – 2 < –12

Adding 2 on both sides;

[tex]2x-2+2<-12+2\\2x<-10[/tex]

Dividing both sides by 2

[tex]\frac{2x}{2}<\frac{-10}{2}\\x<-5[/tex]

Solving the second inequality

2x + 3 > 7

Subtracting 3 from both sides

[tex]2x+3-3>7-3\\2x>4[/tex]

Dividing both sides by 2

[tex]\frac{2x}{2}>\frac{4}{2}\\x>2[/tex]

Therefore;

x< -5 or x>2

The right answer is Option C: x< -5 or x>2

Keywords: inequality, division

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