Answer:
Step-by-step explanation:
The given function g(x) is a continuous function, since, for any x we can find a real value of the function.
A. [tex]\frac{d g(x)}{dx} = 5m(-2x + 2)^{4} \times (-2)[/tex].
Since, m is a constant, which is not equals to 0, the above value of the differentiation of the function, will be negative.
For x = 1, the above value is 0, that is at x = 1, the function has either maximum value, or a minimum value.
B. As per the above information, we have get that for x = 1, [tex]\frac{d g(x)}{dx} = 0[/tex].
Hence, the function's critical point's x coordinate is x = 1.
The x- coordinate of the given point is not dependent on m or n.
Hence, proved.