Answer:
[tex]P = \frac{132000}{12}=11000[/tex]
So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:
[tex] P + 10 (1.1P) = 12 P= 132000[/tex]
[tex]P = \frac{132000}{12}=11000[/tex]
So then P =11000 is the minimum that the least populated district could have.