Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are perpendicular to BC.

Respuesta :

The missing coordinate of point A is x = -7 and of point D is y = 11

Step-by-step explanation:

The product of the slopes of perpendicular lines is -1

Example: If two lines are perpendicular and the slope of one of

them is m, then the slope of the other is [tex]\frac{-1}{m}[/tex]

  • The formula of the slope of a line is [tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
  • [tex](x_{1},y_{1})[/tex] and [tex](x_{1},y_{1})[/tex] are two points on the line

∵ Line Segment BC has endpoints B (3 , 5) and C (7 , 15)

∴ [tex]x_{1}[/tex] = 3 and [tex]x_{2}[/tex] = 7

∴ [tex]y_{1}[/tex] = 5 and [tex]y_{2}[/tex] = 15

- Substitute them in the formula of the slope to find the slope of BC

∴ [tex]m_{BC}=\frac{15-5}{7-3}=\frac{10}{4}[/tex]

- Divide up and down by 2 to reduce it to its simplest form

∴ [tex]m_{BC}=\frac{5}{2}[/tex]

AB ⊥ BC

- Use the rule of the slopes of the perpendicular lines above,

   reciprocal the slope of BC and change its sign

∴ [tex]m_{AB}=\frac{-2}{5}[/tex]

∵ A = (x , 9) and B = (3 , 5)

∴ [tex]x_{1}[/tex] = x and [tex]x_{2}[/tex] = 3

∴ [tex]y_{1}[/tex] = 9 and [tex]y_{2}[/tex] = 5

- Substitute them in the formula of the slope to find the slope of AB

∴ [tex]m_{AB}=\frac{5-9}{3-x}=\frac{-4}{3-x}[/tex]

∵ [tex]m_{AB}=\frac{-2}{5}[/tex]

- Equate the two values of the slope of line AB

∴ ∴ [tex]\frac{-4}{3-x}=\frac{-2}{5}[/tex]

- By using cross multiplication

∴ -4 × 5 = -2 × (3 - x)

∴ -20 = -6 + 2x

- Add 6 to both sides

∴ -14 = 2x

- Divide both sides by 2

-7 = x

∴ The x-coordinate of point A is -7

CD ⊥ BC

- Use the rule of the slopes of the perpendicular lines above,

   reciprocal the slope of BC and change its sign

∴ [tex]m_{CD}=\frac{-2}{5}[/tex]

∵ C = (7 , 15) and D = (17 , y)

∴ [tex]x_{1}[/tex] = 7 and [tex]x_{2}[/tex] = 17

∴ [tex]y_{1}[/tex] = 15 and [tex]y_{2}[/tex] = y

- Substitute them in the formula of the slope to find the slope of CD

∴ [tex]m_{CD}=\frac{y-15}{17-7}=\frac{y-15}{10}[/tex]

∵ [tex]m_{CD}=\frac{-2}{5}[/tex]

- Equate the two values of the slope of line AB

∴ ∴ [tex]\frac{y-15}{10}=\frac{-2}{5}[/tex]

- By using cross multiplication

∴ 5 × (y - 15) = -2 × 10

∴ 5y - 75 = -20

- Add 75 to both sides

∴ 5y = 55

- Divide both sides by 5

y = 11

∴ The y-coordinate of point D is 11

The missing coordinate of point A is x = -7 and of point D is y = 11

Learn more:

You can learn more about the slopes of the perpendicular lines in brainly.com/question/2601054

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