Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for strontium, Sr. 5, 1, 1, ½ 5, 0, 0, –½ 5, 0, 1, ½ 5, 1, 0, ½ 5, 1, 0, –½

Respuesta :

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

The only possible sets of quantum numbers for an electron ion a 5s orbital is as follows; 5, 0, 0, –½

The electron configuration of strontium is; 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s². Strontium is an element in group 2 so it forms a cation when electrons are removed.

The last electrons in the strontium atom are found in the 5s orbital. The only possible sets of quantum numbers for an electron ion a 5s orbital is as follows; 5, 0, 0, –½.

Learn more: https://brainly.com/question/16885872