Answer:
[tex]P =90\times 10^7\ W[/tex]
Explanation:
Given that
Volume flow rate ,Q= 1200 m³ each seconds
So we can say that
Q= 1200 m³ /s
From energy conservation
(Potential energy +kinetic energy ) at top = (Potential energy +kinetic energy ) at bottom
U₁+ KE₁ = U₂+ KE₂
ρ Q g h + 0 = 0 + KE₂
KE₂= ρ Q g h
For water ,ρ = 1000 kg/m³
KE₂=1000 x 1200 x 10 x 100 W ( take g= 10 m/s²)
KE₂=120 x 10⁷ W
Only three forth of the energy converted into electrical energy
Therefore power P
[tex]P=\dfrac{3}{4}\times KE_2[/tex]
[tex]P=\dfrac{3}{4}\times 120\times 10^7\ W[/tex]
[tex]P =90\times 10^7\ W[/tex]
