Problem Page When of urea are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing point of pure . Calculate the mass of iron(III) nitrate that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for iron(III) nitrate in .

Respuesta :

Answer:

51.14 g

Explanation:

When a nonvolatile compound is added to a solvent, the freezing and the boiling point are changed, a process called cryoscopy and ebullioscopy, respectively. To calculate the change in temperature, the equation is:

ΔT = K.W.i

Where K is a constant for the solvent, W is the molality, and i is the van't Hoff factor.

The molality can be calculated by:

W= m1/(M1*m2)

Where m1 is the mass of the solute (in g), M1 is the molar mass of the solute (in g), and m2 is the mass of the solvent (in kg). X is the solvent.

The van't Hoff factor relates to the particles produced when the compound dissociates. For organic compounds, such as urea, we can use i = 1.

So, for Urea, M1 = 60.0 g/mol, m1 = 40.1 g, m2 = 1100 g = 1.10 kg. So:

W = 40.1/(60*1.10)

W = 0.6076 M

3.9 = K*0.6076*1

K = 6.42 °C/M

The value of K is the same indepentend of the solute. So, for iron (III) nitrate:

M1 = 241.86 g/mol, m2 = 1.10 kg, i = 3.16, ΔT = 3.9°C

3.9 = 6.42*W*3.16

20.2872W = 3.9

W = 0.1922

0.1922 = m1/(241.86*1.10)

m1 = 51.14 g