Answer:
35 g of Oxygen will give 59.7 g of SeO3
Explanation:
Atomic number of SeO3 = 34 + 3×16 = 82 g
In this reaction 3 moles of oxygen gives 2 moles of SeO3
therefore one mole of oxygen will give [tex]\frac{2}{3}[/tex] moles of SeO3
that is 32 g of oxygen will give [tex]\frac{2}{3}\times 82[/tex] g of SeO3
therefore 35 g of oxygen will give [tex]\frac{2\times 82\times 35}{3\times 32}[/tex] g of SeO3
=59.7 g of SeO3
