Answer:
Hailstone remained in the cloud for 25 seconds.
Step-by-step explanation:
Radius of a hailstone varies directly with the duration for which it was in the cloud.
Let the radius of the hailstone is 'r' and it was in the cloud for 't' seconds.
r ∝ t
r = kt [ k is the proportionality constant]
If r = 0.5 inches and t = 10 seconds
Then, 0.5 = k × 10
k = [tex]\frac{0.5}{10}[/tex]
k = 0.05
Now we have to find the duration t for which hailstone was in the cloud having radius = 1.25 inches.
1.25 = 0.05 × t
t = [tex]\frac{1.25}{0.05}[/tex]
t = 25 second
Therefore, hailstone remained in the cloud for 25 seconds.
