Answer:
(a) Speed will be 0.03594 m/sec
(b) Speed will be 0.0575 m/sec
Explanation:
(a) We have given volume flow rate [tex]V=2.6\times 10^{-6}m^3/sec[/tex]
Radius of the artery r = 4.8 mm = 0.0048 m
We know that area [tex]A=\pi r^2=3.14\times 0.0048^2=7.234\times 10^{-5}m^2[/tex]
We know that volume flow rate [tex]V=Av[/tex] , here v is velocity
So [tex]2.6\times 10^{-6}=7.234\times 10^{-5}\times v[/tex]
[tex]v=0.03594m/sec[/tex]
(b) Now radius is reduced by factor 4
So new radius = [tex]\frac{4.8}{4}=1.2mm=0.0012m[/tex]
We know that area [tex]A=\pi r^2=3.14\times 0.0012^2=4.5216\times 10^{-6}m^2[/tex]
We know that volume flow rate [tex]V=Av[/tex] , here v is velocity
So [tex]2.6\times 10^{-6}=4.5216\times 10^{-6}\times v[/tex]
[tex]v=0.0575m/sec[/tex]
