coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
Answer:
B: (5,0)
C: (3.5 , 3√3/2)
Step-by-step explanation:
ΔABC: equilateral triangle CA=AB=BC=3
B: (2+3,0) i.e. (5,0)
AD=3/2=1.5
CD²=CA²-AD2 = 9 - 9/4 = 27/4 CD = 3√3 / 2
C: (2 + 3/2, 0 + 3√3/2) i.e. (3.5 , 3√3/2)
