Answer:
0.0392,0.4709, 38083
Step-by-step explanation:
Given that XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of a wedding is $29,858
X is N(29,858, 5600)
Or [tex]Z=\frac{x-29158}{5600}[/tex] is N*(0,1)
We can use std normal distribution table to get the probabilities
a) The probability that a wedding costs less than $20,000 (to 4 decimals)
= [tex]P(X<20000)\\= 0.039174[/tex]
=0.0392
b) the probability that a wedding costs between $20,000 and $30,000
=[tex]0.5101-0.0392\\=0.4709[/tex]
c) For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)
=[tex]29858+1.645*5600\\=38083[/tex]