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A block of mass m=0.750 kg is fastened to an unstrained horizontal spring whose spring constant is k=82.0 N/m. The block is given a displacement of +0.120m, where the + sign indicates that the displacement is along the +x axis, and then released from rest. C) What is the maximum speed of the block? Group of answer choices

Respuesta :

Answer:

13.12 m/s

Explanation:

According to the law of energy conservation, the maximum speed of the block occurs when all the spring potential energy is converted to block kinetic energy. That is:

[tex]E_s = E_k[/tex]

[tex]\frac{1}{2}kx^2 = \frac{1}{2}mv^2[/tex]

[tex]v^2 = \frac{kx^2}{m}[/tex]

[tex]v = \sqrt{\frac{kx^2}{m}} = x\sqrt{\frac{k}{m}}[/tex]

we can substitute m = 0.75 kg, k = 82 N/m, and x = 0.12m

[tex]v = 0.12\frac{82}{0.75} = 13.12 m/s[/tex]