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A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5 maximum does not appear. She had predicted that this bright fringe would be 1.6 cm from the central maximum on a screen 1.5 m behind the slits. What is the width of her slits?

Respuesta :

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

 [tex]y = \dfrac{m\lambda\ D}{d}[/tex]

for the first maxima, m = 1

 [tex]d = \dfrac{1\times \lambda\ D}{y}[/tex]

 [tex]d = \dfrac{1\times  550 \times 10^{-9}\times 1.5}{0.016}[/tex]

       d = 5.2 x 10⁻⁶ m

       d = 52 μm

hence, the width of her slits is equal to d = 52 μm

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