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a car traveling at a constant acceleration covers the distance between two points 180m apart in 6 seconds. if the speed of the car at the speed point is 45 m/s, what is the acceleration of the car ?

Respuesta :

Stefanisaska

Answer: 2.5 m/s²

Explanation:

distance S=180 m

Time       t=6s

Speed at speed point: V2=45 m/s

Acceleration is calculated a=(V2-V1)/t

V1=S/t

V1=180m/6s

V1=30m/s

a=(45m/s-30m/s)/6s

a=15m/s/6s

a=2.5m/s²

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