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There are limitations to the amount of pressure that can be applied during reverse osmosis because of the physical nature of the membrane. A membrane has been developed that can withstand osmotic pressures, Π, of up to 1.52×105 torr . Calculate the maximum molar concentration of a solution that can be purified by reverse osmosis using this membrane at 25 ∘C.

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dsdrajlin

Answer:

8.18 M

Explanation:

The osmotic pressure (π) is a colligative property that can be calculated using the following expression.

π = M . R . T

where,

M: molarity

R: ideal gas constant

T: absolute temperature

The absolute temperature is 25 + 273 = 298 K.

The osmotic pressure (in atm) is:

[tex]1.52 \times 10^{5} torr.\frac{1atm}{760torr} =200atm[/tex]

π = M . R . T

200 atm = M . (0.08206 atm.L/mol.K) . 298 K

M = 8.18 mol/L

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