Answer:
The points are [tex]( x_1 , y_1 )[/tex] = ( 0 , - 2 ) and [tex]( x_2 , y_2 )[/tex] = ( - 3 , 0 )
These points is plotted on the x-y graph
Step-by-step explanation:
Given linear equation as :
4 x + 6 y = - 12
now, Let the points for the equation be
[tex]( x_1 , y_1 )[/tex] and [tex]( x_2 , y_2 )[/tex]
Now, From equation
For, x = 0
4 × 0 + 6 × y = - 12
Or, 0 + 6 × y = - 12
∴ y = [tex]\frac{-12}{6}[/tex]
I.e y = - 2
So, [tex]( x_1 , y_1 )[/tex] = ( 0 , - 2 )
Again
For, y = 0
4 × x + 6 × 0 = - 12
Or, 4 × x + 0 = - 12
∴ x = [tex]\frac{-12}{4}[/tex]
I.e x = - 3
So, [tex]( x_2 , y_2 )[/tex] = ( - 3 , 0 )
So, The points are [tex]( x_1 , y_1 )[/tex] = ( 0 , - 2 ) and [tex]( x_2 , y_2 )[/tex] = ( - 3 , 0 )
Now, These points is plotted on the x-y graph Answer
