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The data and graph below were generated from a collision between Cart
1 (with mass 500 g) and Cart 2 (with mass 250 g) which occurred on a
level, frictionless track what is the total momentum ​

Respuesta :

Answer:

The total momentum of the carts is p = 5000 g cm/s                        

Explanation:

Given data,

The mass of the cart 1, m₁ = 500 g

The mass of the cart 2, m₂ = 250 g      

Let the velocity of the cart 1 be, v₁ = 5 cm/s

The velocity of the cart 2 be, v₂ = 10 cm/s

According to the law of conservation of momentum, then the total momentum of the carts before and after will be the same.

Therefore,

                           p = m₁v₁ + m₂v₂

                               =  500 x 5 + 250 x 10

                                = 5000 g cm/s

Hence, the total momentum of the carts is p = 5000 g cm/s                          

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