Answer:
The probability of rolling a number less than 6 on 1 roll of a die is
[tex]\frac{5}{6}[/tex] = 0.833is
Step-by-step explanation:
Let
S be the sample space for a rolling of a Die
∴ is total number of outcomes for a rolling of a die are ={ one, two, three, four, five, six} six
i.e { 1,2,3,4,5,6}
∴ n (S) = 6
let A be the event of getting a number less than six
then the possible outcomes are { 1, 2, 3, 4, 5 }
∴ n(A) = 5
To Find:
P (A) = ?
Solution:
we know that probability is given by
[tex]\textrm{probability of the event}=\frac{\textrm{possible outcomes of the event}}{\textrm{total number of outcomes}} \\\\\therefore P(A) = \frac{n(A)}{n(S)} \\\\\therefore P(A) =\frac{5}{6}\\ \\\therefore P(A) = 0.833\\[/tex]
