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For the school play, the advance tickets cost $3, while tickets at the door cost $5. There were twice as many tickets sold at the door as were sold in advance, and $4030 was collected. How many of each kind of ticket were sold?

Respuesta :

Answer: B just took the test :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let x represent the number of advance tickets sold

Let y represent the number of tickets sold at the door.

There were twice as many tickets sold at the door as were sold in advance. This means that

y = 2x

For the school play, the advance tickets cost $3, while tickets at the door cost $5 and a total of $4030 was collected. This means that

3x + 5y = 4030 - - - - - - - - - -1

Substituting x = 2y into equation 1. It becomes

3× + 5×2x = 4030

3x + 10x = 4030

13x = 4030

x = 4030/13

x = 310

y = 2x

y = 310×2 = 620 tickets

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