During a snowball fight two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-on and combine to form a single mass. The magnitude of initial velocity for each is 15 m/s. What is the speed of the 1.0-kg mass immediately after collision?

Respuesta :

Answer:

the speed of the snow ball after collision is equal to 3 m/s

Explanation:

given,

mass of the two balls

m₁ = 0.4 Kg

m₂ = 0.6 Kg

initial velocity of each ball = v₁ = 15 m/s

Speed of 1 Kg mass after collision = ?

using conservation of momentum

m₁ v₁ - m₂ v₁ = (m₁+m₂) V

negative velocity shows that second ball is moving in opposite direction.

0.4 x 15 - 0.6 x 15 = (1) V

V = - 3 m/s

Hence,

the speed of the snow ball after collision is equal to 3 m/s

After collision, the speed of snow will be "3 m/s".

Collision

Whenever two things come into interacting directly with one another, this is referred to be a collision. It should be the process through which two or more substances generate pressures on each other throughout a relatively brief period of duration.

According to the question,

Mass of two balls, m₁ = 0.4 kg

                              m₂ = 0.6 kg

Initial velocity, v₁ = 15 m/s

By using Conservation of momentum,

→ m₁v₁ - m₂v₂ = (m₁+m₂)V

By substituting the values, we get

0.4 × 15 - 0.6 × 15 = 1 × V

                    6 - 9 = V            

                         V = -3 or,

                         V = 3 m/s

Thus the above response is correct.

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https://brainly.com/question/7694106