Answer:
1.84 L
Explanation:
Using the equation for reversible work:
[tex]W = -P*(V_{2} - V_{1})[/tex]
Where:
W is the work done (J) = -287 J.
Since the gas did work, therefore W is negative.
P is the pressure in atm = 1.90 atm.
However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K); R = 0.0821 (L*atm)/(mol*K)
Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J
[tex]V_{1}[/tex] is the initial volume = 0.350 L
[tex]V_{2}[/tex] is the final volume = ?
Thus:
(-287 J)*0.00987 (L*atm)/J = -1.9 atm*([tex]V_{2}[/tex] - 0.350) L
[tex]V_{2}[/tex] = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L
